Functor, Applicative, and Monad

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Let's start off with a very simple problem. We want to let a user input his/her birth year, and tell him/her his/her age in the year 2020. Using the function read, this is really simple:

main = do
    putStrLn "Please enter your birth year"
    year <- getLine
    putStrLn $ "In 2020, you will be: " ++ show (2020 - read year)

If you run that program and type in a valid year, you'll get the right result. However, what happens when you enter something invalid?

Please enter your birth year
hello
main.hs: Prelude.read: no parse

The problem is that the user input is coming in as a String, and read is trying to parse it into an Integer. But not all Strings are valid Integers. read is what we call a partial function, meaning that under some circumstances it will return an error instead of a valid result.

A more resilient way to write our code is to use the readMay function, which will return a Maybe Integer value. This makes it clear with the types themselves that the parse may succeed or fail. To test this out, try running the following code:

import Safe (readMay)

main = do
    -- We use explicit types to tell the compiler how to try and parse the
    -- string.
    print (readMay "1980" :: Maybe Integer)
    print (readMay "hello" :: Maybe Integer)
    print (readMay "2000" :: Maybe Integer)
    print (readMay "two-thousand" :: Maybe Integer)

So how can we use this to solve our original problem? We need to now determine if the result of readMay was successful (as Just) or failed (a Nothing). One way to do this is with pattern matching:

import Safe (readMay)

main = do
    putStrLn "Please enter your birth year"
    yearString <- getLine
    case readMay yearString of
        Nothing -> putStrLn "You provided an invalid year"
        Just year -> putStrLn $ "In 2020, you will be: " ++ show (2020 - year)

Decoupling code

This code is a bit coupled; let's split it up to have a separate function for displaying the output to the user, and another separate function for calculating the age.

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided an invalid year"
        Just age -> putStrLn $ "In 2020, you will be: " ++ show age

yearToAge year = 2020 - year

main = do
    putStrLn "Please enter your birth year"
    yearString <- getLine
    let maybeAge =
            case readMay yearString of
                Nothing -> Nothing
                Just year -> Just (yearToAge year)
    displayAge maybeAge

This code does exactly the same thing as our previous version. But the definition of maybeAge in the main function looks pretty repetitive to me. We check if the parse year is Nothing. If it's Nothing, we return Nothing. If it's Just, we return Just, after applying the function yearToAge. That seems like a lot of line noise to do something simple. All we want is to conditionally apply yearToAge.

Functors

Fortunately, we have a helper function to do just that. fmap, or functor mapping, will apply some function over the value contained by a functor. Maybe is one example of a functor, another common one is a list. In the case of Maybe, fmap does precisely what we described above. So we can replace our code with:

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided an invalid year"
        Just age -> putStrLn $ "In 2020, you will be: " ++ show age

yearToAge year = 2020 - year

main = do
    putStrLn "Please enter your birth year"
    yearString <- getLine
    let maybeAge = fmap yearToAge (readMay yearString)
    displayAge maybeAge

Our code definitely got shorter, and hopefully a bit clearer as well. Now it's obvious that all we're doing is applying the yearToAge function over the contents of the Maybe value.

So what is a functor? It's some kind of container of values. In Maybe, our container holds zero or one values. With lists, we have a container for zero or more values. Some containers are even more exotic; the IO functor is actually providing an action to perform in order to retrieve a value. The only thing functors share is that they provide some fmap function which lets you modify their contents.

do-notation

We have another option as well: we can use do-notation. This is the same way we've been writing our main function in so far. That's because- as we mentioned in the previous paragraph- IO is a functor as well. Let's see how we can change our code to not use fmap:

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided an invalid year"
        Just age -> putStrLn $ "In 2020, you will be: " ++ show age

yearToAge year = 2020 - year

main = do
    putStrLn "Please enter your birth year"
    yearString <- getLine
    let maybeAge = do
            yearInteger <- readMay yearString
            return $ yearToAge yearInteger
    displayAge maybeAge

Inside the do-block, we have the slurp operator <-. This operator is special for do-notation, and is used to pull a value out of its wrapper (in this case, Maybe). Once we've extracted the value, we can manipulate it with normal functions, like yearToAge. When we complete our do-block, we have to return a value wrapped up in that container again. That's what the return function does.

do-notation isn't available for all Functors; it's a special feature reserved only for Monads. Monads are an extension of Functors that provide a little extra power. We're not really taking advantage of any of that extra power here; we'll need to make our program more complicated to demonstrate it.

Dealing with two variables

It's kind of limiting that we have a hard-coded year to compare against. Let's fix that by allowing the user to specify the "future year." We'll start off with a simple implementation using pattern matching and then move back to do notation.

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
    let maybeAge =
            case readMay birthYearString of
                Nothing -> Nothing
                Just birthYear ->
                    case readMay futureYearString of
                        Nothing -> Nothing
                        Just futureYear -> Just (futureYear - birthYear)
    displayAge maybeAge

OK, it gets the job done... but it's very tedious. Fortunately, do-notation makes this kind of code really simple:

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

yearDiff futureYear birthYear = futureYear - birthYear

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
    let maybeAge = do
            birthYear <- readMay birthYearString
            futureYear <- readMay futureYearString
            return $ yearDiff futureYear birthYear
    displayAge maybeAge

This is very convenient: we've now slurped our two values in our do-notation. If either parse returns Nothing, then the entire do-block will return Nothing. This demonstrates an important property about Maybe: it provides short circuiting.

Without resorting to other helper functions or pattern matching, there's no way to write this code using just fmap. So we've found an example of code that requires more power than Functors provide, and Monads provide that power.

Partial application

But maybe there's something else that provides enough power to write our two-variable code without the full power of Monad. To see what this might be, let's look more carefully at our types.

We're working with two values: readMay birthYearString and readMay futureYearString. Both of these values have the type Maybe Integer. And we want to apply the function yearDiff, which has the type Integer -> Integer -> Integer.

If we go back to trying to use fmap, we'll seemingly run into a bit of a problem. The type of fmap- specialized for Maybe and Integer- is (Integer -> a) -> Maybe Integer -> Maybe a. In other words, it takes a function that takes a single argument (an Integer) and returns a value of some type a, takes a second argument of a Maybe Integer, and gives back a value of type Maybe a. But our function- yearDiff- actually takes two arguments, not one. So fmap can't be used at all, right?

Not true actually. This is where one of Haskell's very powerful features comes into play. Any time we have a function of two arguments, we can also look at is as a function of one argument which returns a function. We can make this more clear with parentheses:

yearDiff :: Integer -> Integer -> Integer
yearDiff :: Integer -> (Integer -> Integer)

So how does that help us? We can look at the fmap function as:

fmap :: (Integer -> (Integer -> Integer))
     -> Maybe Integer -> Maybe (Integer -> Integer)

Then when we apply fmap to yearDiff, we end up with:

fmap yearDiff :: Maybe Integer -> Maybe (Integer -> Integer)

That's pretty cool. We can apply this to our readMay futureYearString and end up with:

fmap yearDiff (readMay futureYearString) :: Maybe (Integer -> Integer)

That's certainly very interesting, but it doesn't help us. We need to somehow apply this value of type Maybe (Integer -> Integer) to our readMay birthYearString of type Maybe Integer. We can do this with do-notation:

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

yearDiff futureYear birthYear = futureYear - birthYear

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
    let maybeAge = do
            yearToAge <- fmap yearDiff (readMay futureYearString)
            birthYear <- readMay birthYearString
            return $ yearToAge birthYear
    displayAge maybeAge

We can even use fmap twice and avoid the second slurp:

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

yearDiff futureYear birthYear = futureYear - birthYear

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
    let maybeAge = do
            yearToAge <- fmap yearDiff (readMay futureYearString)
            fmap yearToAge (readMay birthYearString)
    displayAge maybeAge

But we don't have a way to apply our Maybe (Integer -> Integer) function to our Maybe Integer directly.

Applicative functors

And now we get to our final concept: applicative functors. The idea is simple: we want to be able to apply a function which is inside a functor to a value inside a functor. The magic operator for this is <*>. Let's see how it works in our example:

import Safe (readMay)
import Control.Applicative ((<*>))

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

yearDiff futureYear birthYear = futureYear - birthYear

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
    let maybeAge =
            fmap yearDiff (readMay futureYearString)
                <*> readMay birthYearString
    displayAge maybeAge

In fact, the combination of fmap and <*> is so common that we have a special operator, <$>, which is a synonym for fmap. That means we can make our code just a little prettier:

import Safe (readMay)
import Control.Applicative ((<$>), (<*>))

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

yearDiff futureYear birthYear = futureYear - birthYear

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
-- show
    let maybeAge = yearDiff
            <$> readMay futureYearString
            <*> readMay birthYearString
-- /show
    displayAge maybeAge

Notice the distinction between <$> and <*>. The former uses a function which is not wrapped in a functor, while the latter applies a function which is wrapped up.

So we don't need Monads?

So if we can do such great stuff with functors and applicative functors, why do we need monads at all? The terse answer is context sensitivity: with a monad, you can make decisions on which processing path to follow based on previous results. With applicative functors, you have to always apply the same functions.

Let's give a contrived example: if the future year is less than the birth year, we'll assume that the user just got confused and entered the values in reverse, so we'll automatically fix it by reversing the arguments to yearDiff. With do-notation and an if statement, it's easy:

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

yearDiff futureYear birthYear = futureYear - birthYear

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
    let maybeAge = do
            futureYear <- readMay futureYearString
            birthYear <- readMay birthYearString
            return $
                if futureYear < birthYear
                    then yearDiff birthYear futureYear
                    else yearDiff futureYear birthYear
    displayAge maybeAge

Exercises

Implement fmap using <*> and return.

import Control.Applicative ((<*>), Applicative)
import Prelude (return, Monad)
import qualified Prelude

fmap :: (Applicative m, Monad m) => (a -> b) -> (m a -> m b)
-- show
fmap ... ... = FIXME
-- /show

main =
    case fmap (Prelude.+ 1) (Prelude.Just 2) of
        Prelude.Just 3 -> Prelude.putStrLn "Good job!"
        _ -> Prelude.putStrLn "Try again"

import Control.Applicative ((<*>))

-- show
myFmap function wrappedValue = return function <*> wrappedValue

main = print $ myFmap (+ 1) $ Just 5
-- /show

How is return implemented for the Maybe monad? Try replacing return with its implementation in the code above.

-- show
returnMaybe = FIXME
-- /show

main
    | returnMaybe "Hello" == Just "Hello" = putStrLn "Correct!"
    | otherwise = putStrLn "Incorrect, please try again"

return is simply the Just constructor. This gets defined as:

instance Monad Maybe where
    return = Just

yearDiff is really just subtraction. Try to replace the calls to yearDiff with explicit usage of the - operator.

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
    let maybeAge = do
            futureYear <- readMay futureYearString
            birthYear <- readMay birthYearString
            return $
-- show
                if futureYear < birthYear
                    then yearDiff birthYear futureYear
                    else yearDiff futureYear birthYear
-- /show
    displayAge maybeAge

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
    let maybeAge = do
            futureYear <- readMay futureYearString
            birthYear <- readMay birthYearString
            return $
-- show
                if futureYear < birthYear
                    then birthYear - futureYear
                    else futureYear - birthYear
-- /show
    displayAge maybeAge

It's possible to write an applicative functor version of the auto-reverse-arguments code by modifying the yearDiff function. Try to do so.

import Safe (readMay)
import Control.Applicative ((<$>), (<*>))

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

-- show
yearDiff futureYear birthYear = FIXME
-- /show

main
    | yearDiff 5 6 == 1 = putStrLn "Correct!"
    | otherwise = putStrLn "Please try again"

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

-- show
yearDiff futureYear birthYear
    | futureYear > birthYear = futureYear - birthYear
    | otherwise = birthYear - futureYear
-- /show

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
    let maybeAge = do
            futureYear <- readMay futureYearString
            birthYear <- readMay birthYearString
            return $
                if futureYear < birthYear
                    then yearDiff birthYear futureYear
                    else yearDiff futureYear birthYear
    displayAge maybeAge

Now try to do it without modifying yearDiff directly, but by using a helper function which is applied to yearDiff.

import Safe (readMay)
import Control.Applicative ((<$>), (<*>))

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

yearDiff futureYear birthYear = futureYear - birthYear
-- show
yourHelperFunction f ...
-- /show

main
    | yourHelperFunction yearDiff 5 6 == 1 = putStrLn "Correct!"
    | otherwise = putStrLn "Please try again"

import Safe (readMay)

displayAge maybeAge =
    case maybeAge of
        Nothing -> putStrLn "You provided invalid input"
        Just age -> putStrLn $ "In that year, you will be: " ++ show age

yearDiff futureYear birthYear = futureYear - birthYear

main = do
    putStrLn "Please enter your birth year"
    birthYearString <- getLine
    putStrLn "Please enter some year in the future"
    futureYearString <- getLine
    let maybeAge = do
            futureYear <- readMay futureYearString
            birthYear <- readMay birthYearString
            return $
                if futureYear < birthYear
                    then yourHelperFunction yearDiff birthYear futureYear
                    else yourHelperFunction yearDiff futureYear birthYear
    displayAge maybeAge

-- show
yourHelperFunction f x y
    | x > y = f x y
    | otherwise = f y x
-- /show

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